RE: [xsl] xsl:include with parameter?

["Michael Kay" <mhk@xxxxxxxxx>]

This is a FAQ, and the answer is that it can't be done. As in most other
programming languages, you can't change the code of the program based on the
data that it reads at run-time.

You'll have to find a different solution to your problem. If you describe
the problem, I expect someone will help with it.

Michael Kay 

> -----Original Message-----
> From: yguaba@xxxxxxxxxxxx [mailto:yguaba@xxxxxxxxxxxx] 
> Sent: 18 June 2004 23:32
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] xsl:include with parameter?
> 
> Hi all,
> 
> I would like to be able to include a file with additional XSL 
> templates in a primary XSL file. That's easy. However, I would like 
> the URI for the "include" file to come from a field in the XML 
> document being processed.
> 
> 
> Example:
> 
> XML snippet:
> 
> <ROOT>
> 	<Parameters>
> 		
> <additional_xsl>/library/xsl/add_stylesheet.xsl</additional_xsl>
> 	</Parameters>
> </ROOT>
> 
> 
> XSL snippet:
> 
> <xsl:param name="additional_xsl" 
> select="/ROOT/Parameters/additional_xsl"/>
> <xsl:include href="{$additional_xsl}"/>
> 
> 
> This doesn't work. It's occurred to me that the XSL document may need 
> to be parsed in its entirety before the XML document is processed. Is 
> that true? Or is there hope for me still? Does anyone have any other 
> ingenious suggestions?
> 
> Thanks in advance,
> 
> Erik
> 
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