Subject: Re: xsl:include with parameter? From: yguaba@xxxxxxxxxxxx Date: Sat, 19 Jun 2004 12:09:20 -0300 |
On 18 Jun 2004 at 23:45, Michael Kay wrote: > This is a FAQ, and the answer is that it can't be done. As in most > other programming languages, you can't change the code of the program > based on the data that it reads at run-time. I apologize, Michael, but I did search the dpawson.co.uk web site and also googled the subject, to no avail. I probably need to work on my searching skills. > You'll have to find a different solution to your problem. If you describe > the problem, I expect someone will help with it. Okay, here's the deal: I have several XSL stylesheets that do different things [obviously] but use a couple of templates that are common to more than one stylesheet and are thus kept in separate "include" files. The choice of additional template to be included depends on a few other factors that have to do with the specificities of my system, and that would take a long time to explain but probably wouldn't add much to this discussion. All XML files are generated by PHP scripts; when an XML file is generated, the script inserts an xml-stylesheet PI indicating which ready-made XSL file is to be used for transformation. That XSL file, in turn, calls (includes) another XSL file containing the additional template(s). For practical reasons, I have to rely on browser-based XSL transformation. As I cannot use PHP's XSL processor, I can't have PHP pass the URI of an include file as a parameter to the XSL file, which I imagine would work. Any suggestions are welcome. And if anyone thinks my whole idea is stupid and that there would be a much simpler way to accomplish what I want, feel free to say so bluntly. Erik
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