Subject: [xsl] node's full content + some modifications in that From: "Földényi Tamás" <ftomi@xxxxxxx> Date: Wed, 21 Jul 2004 14:03:28 +0200 |
Hello, I'm new in xslt. I have an xml such as <?xml version="1.0" encoding="ISO-8859-1"?> <?xml-stylesheet type="text/xsl" href="cdcatalog.xsl"?> <catalog> <cd> <artist><b>Eros</b> <tab/> Ramazzotti</artist> </cd> </catalog> I want to write out the full content of the node artist, but also want some modificiation in that markup: I wanna write out <b>Eros</b>      Ramazotti. (convert <tab /> to some non-breaking space) I figured out that <xsl:copy-of> echo the full content of a node, but in this case, there is no way to do more modification in it, at least I don't know how to do it. So my current version writes out <b>Eros</b> <tab/> Ramazzotti. Current xsl: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> <body> <table> <xsl:for-each select="catalog/cd"> <tr> <td> <xsl:copy-of select="artist"/> </td> </tr> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> In the artist node, there could be more nodes such as <i> <strike>, or something totally differrent, and more special tags like <tab/> that I want to convert to non breaking spaces, or something else. Can you point me what to do? Thanks, Thomas
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