Subject: RE: [xsl] how select all siblings? From: "Hardy Merrill" <HMerrill@xxxxxxxxxxxxxxxx> Date: Wed, 13 Oct 2004 09:37:19 -0400 |
Kenneth, yes I have tried that - I still get Count section_legislators:151 Count sorted_legislators: 1 Remember that <xsl:param name="section_legislators"/> is a node set containing 151 "legislator" nodes. Any idea why the "sorted_legislators" variable only contains 1 node, and not 151 ??? Thanks. Hardy Merrill --------------------------------------------------------------------------------------- Subject: Re: [xsl] how select all siblings? From: Kenneth Stephen <marvin.the.cynical.robot@xxxxxxxxx> Date: Tue, 12 Oct 2004 15:43:27 -0500 Hardy, Have you tried $section_legislators/legistor ? Regards, Kenneth On Tue, 12 Oct 2004 14:42:17 -0400, Hardy Merrill <hmerrill@xxxxxxxxxxxxxxxx> wrote: > Here's a snippet from an XSL style sheet: > > <xsl:template name="display_section"> > <xsl:param name="section_legislators"/> > > <tr><td colspan="4">Count section_legislators:<xsl:value-of > select="count($section_legislators)"/></td></tr> > <xsl:variable name="sorted_legislators"> > <xsl:for-each select="$section_legislators"> > <xsl:sort select="district_type" /> > <xsl:sort select="district_no" > data-type="number" /> > <xsl:sort select="legislator_active_date" > data-type="number" order="descending" /> > <xsl:copy-of select="."/> > </xsl:for-each> > </xsl:variable> > <tr><td colspan="4">Count sorted_legislators: <xsl:value-of > select="count(msxsl:node-set($sorted_legislators))"/></td></tr>
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