RE: [xsl] namespace woes

[<Jarno.Elovirta@xxxxxxxxx>]

Hi,

> I have a xsl stylesheet that uses str:split to convert a value into
> fragment.
>
> e.g.
> ...
> <id>10.20.50</10>
> ...
>
> Becomes
>
> <root xmlns="http://www.w3.org/1999/XSL/Transform";>
>   <pg id=10.20.50>
>     <s>10</s>
>     <s>20</s>
>     <s>50</s>
>   </pg>
> </root>
>
> Everything works great except, my root node is output with the default
> namespace. This causes me much grief when I try to access a
> node by name
> with an XPath expression.
>
> My question is. How do I reference a node in the namespace context as
> noted above,

Just declare xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; in your
stylesheet and then use e.g. xsl:root/xsl:pg/xsl:s

> or how can I prevent str:split from outputting
> the default
> namespace?

Don't set the default namespace to be the XSLT one in the str:split template.

Cheers,

Jarno