Re: [xsl] identity transform filtering nodes

Subject: Re: [xsl] identity transform filtering nodes
From: omprakash.v@xxxxxxxxxxxxx
Date: Wed, 30 Mar 2005 17:55:06 +0530
Hi,
   Thanks. That produced the XML output. But the filtering of html tags
didn't happen. I still get all the html tags in my output.

Cheers,
Omprakash.V



                                                                                                                   
                    Dimitre                                                                                        
                    Novatchev            To:     xsl-list@xxxxxxxxxxxxxxxxxxxxxx                                   
                    <dnovatchev@g        cc:     (bcc: omprakash.v/Polaris)                                        
                    mail.com>            Subject:     Re: [xsl] identity transform filtering nodes                 
                                                                                                                   
                    03/30/2005                                                                                     
                    05:49 PM                                                                                       
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> I have checked the archive and the solution I got is probably right but
Iam
> not sure how to make it suit me.
>
> The solution given was
>
>  <xsl:template match="@*|node()">
>     <xsl:copy>
>     <xsl:copy-of select="@*"/>
>     <xsl:apply-templates select="@*|node()"/>
>     </xsl:copy>
>   </xsl:template>
>
> and override the templates for the elements you don't want in your result
> tree here to produce nothing:


This is *not* the identity rule!

Find the correct one at:

   http://www.w3.org/TR/xslt#copying


Cheers,
Dimitre Novatchev






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