Subject: Re: [xsl] transforming XML to XML with XSLT 1.0 From: "Mark Kersten" <markker83@xxxxxxxxxxx> Date: Fri, 20 May 2005 16:32:30 +0200 |
Your requested output format didn't appear to group the elements with the same aid by anything other than the top level element so it's not clear how you want multiple aid values reporting, similarly it's not clear what you are supposed to do if the aid values are the same but the type or version numbers are different.
Basically assuming that aid, type and version are the key that you want to group on, you want to use muenchian grouping with a key of match="Row" use="concat(@AID,':',@GROUP_TYPE,':',@GROUP_VERSION)
and then, for the nodes in each group do the for-each that I posted last time.
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] transforming XML to XML w, David Carlisle | Thread | RE: [xsl] relative path from one no, Ross, Douglas |
RE: [xsl] Functions Returning Nodes, Michael Kay | Date | Re: [xsl] relative path from one no, JBryant |
Month |