Re: [xsl] transforming XML to XML with XSLT 1.0

Subject: Re: [xsl] transforming XML to XML with XSLT 1.0
From: "Mark Kersten" <markker83@xxxxxxxxxxx>
Date: Fri, 20 May 2005 16:32:30 +0200
Your requested output format didn't appear to group the elements  with
the same aid by anything other than the top level element so it's not
clear how you want multiple aid values reporting, similarly  it's not
clear what you are supposed to do if the aid values are the same but the
type or version numbers are different.

This will never happen, the only key is the AID. Type or version can only be listed once in the output xml file.


Basically assuming that aid, type and version are the key that you want
to group on, you want to use muenchian grouping with a key of
match="Row" use="concat(@AID,':',@GROUP_TYPE,':',@GROUP_VERSION)

and then, for the nodes in each group do the for-each that I posted last
time.

I will try that, thanks.


Current Thread