Subject: RE: [xsl] Identity without namespaces From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Sun, 2 Oct 2005 21:10:29 +0100 |
It's basically OK. But your match="/" template is the same as the built-in template for document nodes; and you only want the match="node()" template to handle elements, so it would be better to say so by writing match="*". You need to be aware that if your source document contains attributes such as xml:space, xml:lang, or xsi:type, they will get mangled. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Joe Fawcett [mailto:joefawcett@xxxxxxxxxxx] > Sent: 02 October 2005 19:01 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Identity without namespaces > > Dear All > > I'm trying to write a transform that is basically an identity > transform but > without any namespaces being copied. > I know this is easier in version 2.0 but would anyone comment > on my effort > below, it seems to work but have I missed anything or could > it be simplified? > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > > <xsl:template match="/"> > <xsl:copy> > <xsl:apply-templates select="node()|@*"/> > </xsl:copy> > </xsl:template> > > > <xsl:template match="@*"> > <xsl:attribute name="{local-name()}"> > <xsl:value-of select="." /> > </xsl:attribute> > </xsl:template> > > <xsl:template match="comment() | processing-instruction() | text()"> > <xsl:copy /> > </xsl:template> > > <xsl:template match="node()"> > <xsl:element name="{local-name()}"> > <xsl:apply-templates select="node()|@*"/> > </xsl:element> > </xsl:template> > > </xsl:stylesheet> > > > Thanks > > Joe
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