RE: [xsl] Identity without namespaces

Subject: RE: [xsl] Identity without namespaces
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Sun, 2 Oct 2005 21:10:29 +0100
It's basically OK.

But your match="/" template is the same as the built-in template for
document nodes; and you only want the match="node()" template to handle
elements, so it would be better to say so by writing match="*".

You need to be aware that if your source document contains attributes such
as xml:space, xml:lang, or xsi:type, they will get mangled. 

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Joe Fawcett [mailto:joefawcett@xxxxxxxxxxx] 
> Sent: 02 October 2005 19:01
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Identity without namespaces
> 
> Dear All
> 
> I'm trying to write a transform that is basically an identity 
> transform but 
> without any namespaces being copied.
> I know this is easier in version 2.0 but would anyone comment 
> on my effort 
> below, it seems to work but have I missed anything or could 
> it be simplified?
> 
> <xsl:stylesheet version="1.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> 
>   <xsl:template match="/">
>     <xsl:copy>
>       <xsl:apply-templates select="node()|@*"/>
>     </xsl:copy>
>   </xsl:template>
> 
> 
>   <xsl:template match="@*">
>     <xsl:attribute name="{local-name()}">
>       <xsl:value-of select="." />
>     </xsl:attribute>
>   </xsl:template>
> 
>   <xsl:template match="comment() | processing-instruction() | text()">
>     <xsl:copy />
>   </xsl:template>
> 
>   <xsl:template match="node()">
>     <xsl:element name="{local-name()}">
>       <xsl:apply-templates select="node()|@*"/>
>     </xsl:element>
>   </xsl:template>
> 
> </xsl:stylesheet>
> 
> 
> Thanks
> 
> Joe 

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