Subject: RE: RE: [xsl] Creating XPath2 functions:passing a set of nodes, what is the signature construction? From: cknell@xxxxxxxxxx Date: Wed, 25 Jan 2006 17:09:35 -0500 |
Thanks, I couldn't find that. On closer examination, it seems the standard set of XPath2 functions does not include a square root function. I don't feel up to writing my own, so I won't procede with the standard deviation function. -- Charles Knell cknell@xxxxxxxxxx - email -----Original Message----- From: Xia Li <xli@xxxxxxxxxxxxx> Sent: Wed, 25 Jan 2006 13:46:02 -0800 To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Subject: RE: [xsl] Creating XPath2 functions:passing a set of nodes, what is the signature construction? You may use occurrence indicator "*" or "+" in <xsl:param>, such as <xsl:param ... as="xs:double*"> to indicate that a sequence of double is expected. Lisa -----Original Message----- From: cknell@xxxxxxxxxx [mailto:cknell@xxxxxxxxxx] Sent: Wednesday, January 25, 2006 1:26 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Creating XPath2 functions:passing a set of nodes, what is the signature construction? I am learning XPath2 using Saxon 8.6. I'd like to create a funtion to compute the standard deviation of the value of a set of nodes. Is there some special way to construct the signature of the function when the argument is a set of nodes as opposed to a single node? I have written a funtion that takes a single node as an argument of type xs:double. Is there some special way to state that the function will take a set of nodes of type xs:double, or do I simply state that the argument will be of type xs:double? -- Charles Knell cknell@xxxxxxxxxx - email
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