RE: [xsl] Printing all child bachelor nodes

[cknell@xxxxxxxxxx]

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
 <xsl:output method="text" indent="yes" />
 <xsl:strip-space elements="*" />

 <xsl:template match="/">
   <xsl:apply-templates />
 </xsl:template>

 <xsl:template match="features">
   <xsl:apply-templates />
 </xsl:template>

 <xsl:template match="*[not(local-name()='features')]">
<xsl:value-of select="local-name()" />
 <xsl:choose>
<xsl:when test="count(@*) = 0"><xsl:text>&#010;</xsl:text></xsl:when>
<xsl:otherwise><xsl:text>:&#009;</xsl:text></xsl:otherwise>
 </xsl:choose>
 <xsl:apply-templates select="@*" />
 </xsl:template>

 <xsl:template match="@*">
<xsl:value-of select="local-name()" /><xsl:text>:</xsl:text><xsl:value-of select="." />
<xsl:if test="not(position() = last())"><xsl:text>&#009;</xsl:text></xsl:if>
<xsl:if test="position() = last()"><xsl:text>&#010;</xsl:text></xsl:if>
 </xsl:template>

</xsl:stylesheet>
--
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     Douglas F Shearer <dougal.s@xxxxxxxxx>
Sent:     Thu, 9 Feb 2006 15:08:59 +0000
To:       xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  [xsl] Printing all child bachelor nodes

 Hi there.

 I have the following snippet of XML and would like to extract the  
data given below using XSL...

********** XML ************
<features>
	<pool length="30" max-depth="160" min-depth="30" indoor="false"/>
	<DVD/>
	<beds twin="2" sofa-bed="1"/>
</features>

******** REQUIRED OUTPUT ******
pool: length: 30, max-depth:160, min-depth:30, indoor: false.
DVD.
beds: twin:2, sofa-bed:1

**************************************

 The main issue I am having is that the nodes themselves change  
(microwave instead of DVD etc). Basically I want to print out all of  
the elements within the features element, and their associated  
attributes.

 Help much appreciated.

Dougal.

Douglas F Shearer
dougal.s@xxxxxxxxx
http://douglasfshearer.dyndns.org