Re: [xsl] Stylesheet to output XML Tags (node names)

Subject: Re: [xsl] Stylesheet to output XML Tags (node names)
From: "António Mota" <amsmota@xxxxxxxxx>
Date: Thu, 20 Apr 2006 20:29:52 +0100
I changed the stylesheet to output also attributes, and changed a few things:

<?xml version='1.0' encoding='ISO-8859-1'?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
	<xsl:key name="nodenames" match="*" use="name()" />
	<xsl:template match="/">
		<nodes>
			<xsl:apply-templates select="*[count(. | key('nodenames', name())[1]) =
1]"/>
		</nodes>
	</xsl:template>
	<xsl:template match="*">
		<node>
			<xsl:attribute name="name">
				<xsl:value-of select="name()" />
			</xsl:attribute>
			<xsl:apply-templates select="@*"/>
		</node>
		<xsl:apply-templates select="*[count(. | key('nodenames', name())[1]) =
1]"/>
	</xsl:template>
	<xsl:template match="@*">
		<attr>
			<xsl:attribute name="name">
				<xsl:value-of select="name()" />
			</xsl:attribute>
		</attr>
	</xsl:template>
</xsl:transform>

Current Thread