[xsl] Fwd: Multiple OR Expression across a node-set

My Sincerest apologizes, I accidentally sent this to the xml list.

Hi List,

Thanks in advance for the help. I think I left my brain in Cuba, and
cannot seem to figure out this fairly straight forward problem (well
that and secretly hoping someone has a more elegant way of doing
this).

So I have a generated XML

<root>
<view>
  <id>foo</id>
  <name>foo</name>
</view>
<view>
 <id>bar_archive</id>
 <name>Bar Archive</name>
</view>
<view>
 <id>bar</id>
 <name>bar</name>
</view>
<view>
 <id>foo_archive</id>
 <name>Foo Archive</name>
</view>
</root>

Issue comes from the fact that every time I get this XML file, the
<view>s are in different, random order. I need them in a specific
order every time. Along with this, sometimes a <view> exists, and
sometimes it doesn't which should be reflected in the output. So far
my XSL looks something like this (I've marked where my if statement is
failing):

<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:template match="/">

<html>
<body>
<!-- This if statement fails (Value of expression cannot be converted
to a node-set in expression) -->
<xsl:if test="root//view/id = 'foo' | root//view/id = 'bar'">
 <p>Here are the foo bars</p>
 <ul>
 <xsl:apply-templates select="root//view[id='bar']"/>
 <xsl:apply-templates select="root//view[id='foo']"/>
 </ul>
</xsl:if>

<xsl:if test="contains(root//view/id, 'archive')">
       <p>Here are archive foo bars</p>
       <blockquote>
       <xsl:apply-templates select="root//view[id = 'bar_archive']"/>
       <xsl:apply-templates select="root//view[id = 'foo_archive']"/>
       </blockquote>
</xsl:if>

</body>
</html>

</xsl:template>

<xsl:template match="view" priority="5">
<li><xsl:value-of select="name"/></li>
</xsl:template>

<xsl:template match="view[contains(id, 'archive')]" priority="10">
<p><xsl:value-of select="name"/></p>
</xsl:template>

</xsl:stylesheet>

Any thoughts would be greatly appreciated. (PS - I am stuck with 1.0)

Thanks you,

Spencer Tickner

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