Re: [xsl] Getting the root namespace from the input document

["Mukul Gandhi" <gandhi.mukul@xxxxxxxxx>]

On 2/5/07, Andrew Welch <andrew.j.welch@xxxxxxxxx> wrote:
> <xsl:template match="/">
>        <Metadata>
>                <xsl:copy-of select="namespace::node()"/>
>        </Metadata>
> </xsl:template>

I think Andrew means:

<xsl:template match="/manifest">
  <Metadata>
     <xsl:copy-of select="namespace::*"/>
  </Metadata>
</xsl:template>

But namespace:: axis is deprecated in XSLT 2.0 (though, Saxon supports it)

If you are using XSLT 2.0, the following is perhaps a portable way:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="2.0">

<xsl:output method="xml" indent="yes" />

<xsl:template match="manifest">
 <xsl:variable name="x" select="." />
 <Metadata>
   <!-- create namespace declarations -->
   <xsl:for-each select="in-scope-prefixes($x)">
     <xsl:namespace name="{.}"><xsl:value-of
select="namespace-uri-for-prefix(., $x)" /></xsl:namespace>
   </xsl:for-each>

   <!-- do rest of things -->
 </Metadata>
</xsl:template>

</xsl:stylesheet>

--
Regards,
Mukul Gandhi