Re: [xsl] Xsl:variable content should be empty

[Ronan Klyne <ronan.klyne@xxxxxxxxxxx>]

This line:
<xsl:variable name="link" select="file_link"> </xsl:variable>
specifies the value of the variable twice - as the result of evaluating
'file_link', and as " " (the contents of the variable element).

You probably want to use:
<xsl:variable name="link" select="file_link" />
and to read up on xsl:variable in the XSL specification.

	# r

Alan Hale wrote:
> I'm a relative newcomer to xslt and I wonder if someone could kindly
> explain to me what is the issue with the following use of xsl:variable
> and how I can correct it:
> 
>       <xsl:for-each select="/fieldguide/account">
>             
>       <xsl:variable name="link" select="file_link"> </xsl:variable>
> 	.
> 	.
> 	<td><a target = "_parent" href="{$link}"><xsl:value-of
> select="species_name"/></a></td>
> 	.
> 	.
> 	</xsl:for-each>
> 
> Here is a fragment of the XML:
> 
> <fieldguide>
>   <account> 
>      <species_name>Octodiceras fontanum</species_name>
>      <file_link>../accounts/mosses/Octodiceras
> fontanum_DMT.pdf</file_link>
>      .
>      .	
>   </account>
> </fieldguide>
> 
> 
> As you can see, I am trying to construct an html link from the filename
> and path held in the <file_link> element.
> 
> This works fine when I call the stylesheet in-line or from Javascript in
> Internet Explorer, but when I run it with the PHP XSL extension, it
> generates a warning: Xsl:variable content should be empty since select
> is present. It's only a warning and the output is still as expected, but
> clearly I'm doing something wrong.
> 
>>From reading up it seems to me this IS an xslt issue rather than a PHP
> one. I just don't understand it.
> 
> Glad of any help.
> 
> Alan Hale
> Aberystwyth
> Wales
> 
> 
> 
> 	
> 


-- 
Ronan Klyne
Business Collaborator Developer
Tel: +44 (0)870 163 2555
ronan.klyne@xxxxxxxxxxx
www.groupbc.com