Subject: Re: [xsl] XPath MOD 10 calculation From: Abel Braaksma <abel.online@xxxxxxxxx> Date: Thu, 24 May 2007 15:01:13 +0200 |
sum( for $i in $x[position() mod 2 = 1] return $i * 3, for $i in $x[position() mod 2 = 0] return $i, = number(substring(., string-length(.) - 1, 1))
sum( for $i in $x[position() mod 2 = 1] return $i * 3, $x[position() mod 2 = 0]) = number(substring(., string-length(.) - 1, 1))
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