Subject: [xsl] Finding the current node type From: "Mark Anderson" <mark.anderson@xxxxxxxxxxxxxxxxxxx> Date: Wed, 1 Aug 2007 14:36:40 +0100 |
Thanks Guys In my application, I will only need to process a few hundred nodes and about 20-30 of the type where I need to use the choose statement. I went with the <xsl:if test=self::speaker> option as I still use the namespace (e.g. <xsl:if test=self::abc:speaker>). Whereas localname returned the node name without the ns prefix Thanks for the help Regards mark
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