Re: [xsl] Accessing attribute in a variable with conditional value

Subject: Re: [xsl] Accessing attribute in a variable with conditional value
From: "Wasiq Shaikh" <wasiq911@xxxxxxxxxxx>
Date: Wed, 01 Aug 2007 14:51:57 -0400
Ah, I see! When I printed the variable it "looked" like a nodeset, so I assumed I could access the elements and attributes within.

This is my working solution after applying Mukul's suggestion. Thanks Mukul!

<xsl:variable name="validAttributeType">
<xsl:if test="key('allTypes', @type)">
<xsl:copy-of select="key('allTypes', @type)/xsd:restriction"/>
</xsl:if>
<xsl:if test="xsd:simpleType">
<xsl:copy-of select="xsd:simpleType/xsd:restriction"/>
</xsl:if>
</xsl:variable>
<xsl:if test="$validAttributeType!=''">
<xsl:element name="validValues">
<xsl:call-template name="trimAttribute">
<xsl:with-param name="attributeName" select="'base'"/>
<xsl:with-param name="attribute" select="xalan:nodeset($validAttributeType)/*/@base"/>
</xsl:call-template>
<xsl:for-each select="xalan:nodeset($validAttributeType)/*/*">
<xsl:element name="value">
<xsl:attribute name="type">
<xsl:value-of select="substring-after(name(), 'xsd:')"/>
</xsl:attribute>
<xsl:value-of select="@value"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:if>


(using XalanJ 2.7/XPath 1.0)


----Original Message Follows----


The error you are getting at this line, <xsl:with-param
name="attribute" select="$validAttributeType/@base"/>

is because the variable "validAttributeType" is a result tree fragment
(it's a special data type defined in XSLT 1.0), and you are trying to
apply an XPath operation to it; which is not correct.

To my opinion, you need to use an extension function node-set for this
(if you are restricted to XSLT 1.0).

So for example, something like following will work:
<xsl:with-param name="attribute"
select="xx:node-set($validAttributeType)/xsd:restriction/@base"/>

(please bind the prefix xx to the required namespace - please see the
product documentation for this)

With XSLT 2.0, you will not get the error at all, for the operation
you are trying to do (because XSLT 2.0 implicitly treats the contents
of xsl:variable in this case as a node-set).

On 8/1/07, Wasiq Shaikh <wasiq911@xxxxxxxxxxx> wrote:
> Hi,
>
> I'm setting a value on a variable using conditions. The variable must be a
> node-set so that I can do some processing with it.
>
> <xsl:variable name="validAttributeType">
> <xsl:if test="key('allTypes', @type)">
> <xsl:copy-of select="key('allTypes', @type)/xsd:restriction"/>
> </xsl:if>
> <xsl:if test="xsd:simpleType"
> <xsl:copy-of select="xsd:simpleType/xsd:restriction"/>
> </xsl:if>
> </xsl:variable>
>
> The "xsd:restriction" tag has a "base" attribute that I need to access and
> send to a template as a parameter.
>
> <xsl:call-template name="trimAttribute">
> <xsl:with-param name="attributeName" select="'base'"/>
> <xsl:with-param name="attribute"
> select="$validAttributeType/@base"/>
> </xsl:call-template>
>
> But it gives me a "XSLT Error (javax.xml.transform.TransformerException):
> org.apache.xpath.objects.XRTreeFrag" when I try to do
>
> <xsl:with-param name="attribute" select="$validAttributeType/@base"/>
> OR
> <xsl:with-param name="attribute"><xsl:copy-of
> select="$validAttributeType/@base"/></xsl:with-param>
>
> I can print out the variable's contents, which is correct, but I can't seem
> to access the attribute. By the way, previously I had this
>
> <xsl:variable name="validAttributeType" select="key('allTypes',
> @type)/xsd:restriction"/>
>
> which works! But adding the conditional messed it up. How can I get the same
> behaviour as the above line in a conditional variable?
>
> I appreciate any help. Thank you!



-- Regards, Mukul Gandhi

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