Subject: Re: [xsl] extend an xslt template defined elsewhere? From: "Anthony Ettinger" <anthony@xxxxxxxxx> Date: Fri, 19 Oct 2007 19:40:03 -0700 |
It probably wouldn't, but is something I'd rather not see in the source. Its too bad <xsl:attribute-set> doesn't support xsl:if or xsl:choose. On 10/19/07, Scott Trenda <Scott.Trenda@xxxxxxxx> wrote: > That was one of my caveats that I said at the very beginning. Only > <xsl:attribute> elements can be children of <xsl:attribute-set>, so you > can't wrap them in <xsl:if>. > > Why would an empty class attribute invalidate your result document? > > ~ Scott > > > -----Original Message----- > From: ettinger@xxxxxxxxx [mailto:ettinger@xxxxxxxxx] On Behalf Of > Anthony Ettinger > Sent: Friday, October 19, 2007 6:17 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] extend an xslt template defined elsewhere? > > On 10/19/07, Scott Trenda <Scott.Trenda@xxxxxxxx> wrote: > > > If this IS the case, you can do this: > > > > <xsl:import href="docbook.xsl"/> > > <xsl:attribute-set name="glossdef"> > > <xsl:attribute name="class"> > > <xsl:value-of select="@role"/> > > </xsl:attribute> > > </xsl:attribute-set> > > > > > I still have an empty class attribute in my html output. > > > > > > > > > > -- > Anthony Ettinger > Ph: 408-656-2473 > var (bonita, farley) = new Dog; > farley.barks("very loud"); > bonita.barks("at strangers"); > > http://chovy.dyndns.org/resume/ > http://utuxia.com/consulting > > -- Anthony Ettinger Ph: 408-656-2473 var (bonita, farley) = new Dog; farley.barks("very loud"); bonita.barks("at strangers"); http://chovy.dyndns.org/resume/ http://utuxia.com/consulting
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