Subject: Re: [xsl] Find the node with maximum elements From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx> Date: Mon, 5 Nov 2007 23:31:53 +0530 |
Nice solution, Scott. On 11/5/07, Scott Trenda <Scott.Trenda@xxxxxxxx> wrote: > This may be better represented with 2.0's grouping facilities, but > here's the 1.0 solution I'd use to alleviate Mukul's concerns (building > off Michael's response with <xsl:sort/>): > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > > <xsl:key name="cars" match="*[Car]" use="count(Car)"/> > > <xsl:template match="Sample"> > > <xsl:variable name="max-cars"> > <xsl:for-each select=".//*[Car]"> > <xsl:sort select="count(Car)" data-type="number"/> > <xsl:if test="position() = last()"> > <xsl:value-of select="count(Car)"/> > </xsl:if> > </xsl:for-each> > </xsl:variable> > > <xsl:for-each select="key('cars', $max-cars)"> > <!-- do whatever you'd do with the results here --> > <xsl:value-of select="name()"/> > </xsl:for-each> > > </xsl:template> > > </xsl:stylesheet> > > ~ Scott -- Regards, Mukul Gandhi
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