Re: [xsl] Find the node with maximum elements

Subject: Re: [xsl] Find the node with maximum elements
From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx>
Date: Mon, 5 Nov 2007 23:31:53 +0530
Nice solution, Scott.

On 11/5/07, Scott Trenda <Scott.Trenda@xxxxxxxx> wrote:
> This may be better represented with 2.0's grouping facilities, but
> here's the 1.0 solution I'd use to alleviate Mukul's concerns (building
> off Michael's response with <xsl:sort/>):
>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>
>  <xsl:key name="cars" match="*[Car]" use="count(Car)"/>
>
>  <xsl:template match="Sample">
>
>    <xsl:variable name="max-cars">
>      <xsl:for-each select=".//*[Car]">
>        <xsl:sort select="count(Car)" data-type="number"/>
>        <xsl:if test="position() = last()">
>          <xsl:value-of select="count(Car)"/>
>        </xsl:if>
>      </xsl:for-each>
>    </xsl:variable>
>
>    <xsl:for-each select="key('cars', $max-cars)">
>      <!-- do whatever you'd do with the results here -->
>      <xsl:value-of select="name()"/>
>    </xsl:for-each>
>
>  </xsl:template>
>
> </xsl:stylesheet>
>
> ~ Scott


-- 
Regards,
Mukul Gandhi

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