Re: [xsl] Using a sequence of years to select documents to display in a table row

Subject: Re: [xsl] Using a sequence of years to select documents to display in a table row
From: "Michael Tracey Zellmann" <tracey.zellmann@xxxxxxxxx>
Date: Fri, 23 Nov 2007 17:36:48 -0500
Thanks you both ! Worked well and that is much cleaner.

On Nov 23, 2007 5:02 PM, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> >
> >    <xsl:variable name="docs" select="documents/document"/>
> >    <xsl:for-each select="1842 to 1862">
> >       <tr><td><xsl:value-of select="."/></td>
> >       <td>
> >          <xsl:apply-templates select="$docs[year = . and
> > contains(title, 'Selectmen')"/>
>
> I suspect this should be
>
>   <xsl:apply-templates select="$docs[year = current() and contains(title,
> 'Selectmen')"/>
>
> Michael Kay
> http://www.saxonica.com/

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