Subject: Re: [xsl] An (almost) identity stylesheet From: Jeff Sese <jeferson.sese@xxxxxxxxxxxx> Date: Thu, 10 Apr 2008 16:49:16 +0800 |
<template match="@attrib2"> <xsl:attribute name="@attrib2" select="'0'"/> </template>
Hi list,
I am a novice to XSLT, learned mainly form online tutorials. This XSLT thing is killing me. Can't figure out how to transform my doc.xml:
<?xml version="1.0" encoding="UTF-8"?> <foo> <bar> <date attrib1='aaaaaaa' attrib2='bbbbbb'>25-02-08</date> ^ <name attrib3='null'>AAAAAAAAAAAAAAA</name> </bar> <bar> <date attrib1='cccccc' attrib2='dddddd'>26-02-08</date> ^ <name attrib4='null'>BBBBBBBBBBBBBBB</name> </bar> </foo>
into
<?xml version="1.0" encoding="UTF-8"?> <foo> <bar> <date attrib1='aaaaaaa' attrib2='0'>25-02-08</date> ^ <name attrib3='null'>AAAAAAAAAAAAAAA</name> </bar> <bar> <date attrib1='cccccc' attrib2='0'>26-02-08</date> ^ <name attrib4='null'>BBBBBBBBBBBBBBB</name> </bar> </foo>
Can somebody please suggest the correct stylesheet?
I am blindly typing mainly 'copy' or 'copy-of' in my templates and the
output generation mechanics make little sense to me. The docs, comparing
to other programing documentation seems hard to understand. Could
somebody suggest good docs, please?
Regards, Karol
Jeferson L. Sese jeferson dot sese at asiatype dot com Asiatype Inc. Suite 114 Columbia Tower Ortigas Ave., Greenhills Mandaluyong City 1550 Philippines Tel: +632-744-6262 Mobile: +63927-671-7901
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