Subject: RE: [xsl] Cannot process a result tree fragment as a node-set under XSLT 1.0 - My alternative don´t function From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Sat, 12 Apr 2008 20:03:26 +0100 |
It's not always possible to get by without using result tree fragments but it is possible in this case. And in general, if you can write <xsl:variable name="x"> <xsl:when test="condition1"> <xsl:copy-of select="exp1"/> </xsl:when> <xsl:otherwise> <xsl:copy-of select="exp2"/> </xsl:otherwise> </xsl:variable> then you can probably replace it with <xsl:variable name="x" select="exp1[condition1] | exp2[condition2]"/> which avoids the cost of copying the nodes, and avoids the RTF problem. Of course an even better solution is to move to XSLT 2.0. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Alejandro [mailto:alexcontini@xxxxxxxx] > Sent: 12 April 2008 18:50 > To: mike@xxxxxxxxxxxx > Cc: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] Cannot process a result tree fragment as a > node-set under XSLT 1.0 - My alternative don4t function > > Hi Michael, > > Thank you so much for the quick response. > > Michael >>However, it's not clear to me that you need to > create an RTF in the first place. Why not define $filter as > <xsl:variable name="filter" select="//RecursoEx1[($option=1 and > F_FIN=$date1 and contains(TITULO,'o')) or ($option=2 and > F_FIN=$date2)]"/> > > I want to count the RecursoEx1 elements: > <p>Number: <xsl:value-of > select="count(exsl:node-set($filter)/RecursoEx1)"/></p> CORRECT! > > I want to iterate over the RecursoEx1 elements: > <xsl:for-each select="exsl:node-set($filter)/RecursoEx1"> > CORRECT ! > > I use xsl:copy-of and exsl:node-set because to error "Cannot > process a result tree fragment as a node-set under XSLT 1.0" > if i code : > > <xsl:variable name="filtro"> > <xsl:choose> > <xsl:when test="$option=1"> > <xsl:copy-of > select="//RecursoEx1[F_FIN=$date1]"/></xsl:when> > <xsl:otherwise> > <xsl:copy-of > select="//RecursoEx1[F_FIN=$date2]"/></xsl:otherwise> > </xsl:choose> > </xsl:variable> > > <p>Number: <xsl:value-of select="$filter"/></p> > > <xsl:for-each select="$filter"> > <p><xsl:value-of select="TITULO"/></p> > </xsl:for-each> > > > and i don4t know if exits another posibility. Exists?? > > The variable "option" is to received from one formulary, but > there are more and then the "filter" will be dynamic. > > How can i do to construct the filter dynamic? For example, i > receive one varible named "title" from the formulary with the > value: "John Martin Car Monday" and i like to enumerate the > RecursoEx1 elements that meet with this > condition: TITLE=John or TITLE=Martin or TITLE=Car or TITLE=Monday. > > or title variable is Apple Pencil, ..... then the condition > will be TITLE=Apple or TITLE=Pencil > > i don4t know how may parameters i will receive in advance.. > > Thanks again Michael, > > Alexander > > > ----- Mensaje original ----- > De: "Michael Kay" <mike@xxxxxxxxxxxx> > Para: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> > Enviado: sabado, 12 de abril de 2008 14:03 > Asunto: RE: [xsl] Cannot process a result tree fragment as a > node-set under XSLT 1.0 - My alternative don4t function > > > The node-set returned by the exsl:node-set() function will > always contain a single (document or root) node. Perhaps you > wanted its children: > exsl:node-set()/*. > > However, it's not clear to me that you need to create an RTF > in the first place. Why not define $filter as > > <xsl:variable name="filter" > select="//RecursoEx1[($option=1 and F_FIN=$date1 and > contains(TITULO,'o')) > or ($option=2 and F_FIN=$date2)]"/> > > Note also, that horrible bit of disable-output-escaping can > be avoided by setting the doctype-system and doctype-public > attributes on xsl:output. > > Michael Kay > http://www.saxonica.com/ > > > > -----Original Message----- > > From: Alejandro [mailto:alexcontini@xxxxxxxx] > > Sent: 12 April 2008 13:05 > > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > > Subject: [xsl] Cannot process a result tree fragment as a node-set > > under XSLT 1.0 - My alternative don4t function > > > > Hello, i want to recover any records in function of one variable > > (option in this case), and i don4t know to do it. I want to > print the > > TITULO element the those records. > > Can you help me, please? > > > > Cheers, > > Alexander > > > > > > ********************************* XML > > ************************************* > > > > <?xml version="1.0"?> > > > > <List> > > <RecursoEx1> > > <TITULO>Sara Baras</TITULO> > > <F_INICIO>20080125000000</F_INICIO> > > <F_FIN>20080211000000</F_FIN> > > </RecursoEx1> > > > > <RecursoEx1> > > <TITULO>Exposicion de pintura</TITULO> > > <F_INICIO>20080201000000</F_INICIO> > > <F_FIN>20080211000000</F_FIN> > > </RecursoEx1> > > > > <RecursoEx1> > > <TITULO>Inaguracion de ...</TITULO> > > <F_INICIO>20080205000000</F_INICIO> > > <F_FIN></F_FIN> > > </RecursoEx1> > > > > <RecursoEx1> > > <TITULO>Clausura de ..</TITULO> > > <F_INICIO>20080101000000</F_INICIO> > > <F_FIN>20080205000000</F_FIN> > > </RecursoEx1> > > > > </List> > > > > > > ********************** XSL ********************** > > > > <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet > > xmlns:i18n="http://apache.org/cocoon/i18n/2.0" > > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > > xmlns:exsl="http://exslt.org/common" > > extension-element-prefixes="exsl" version="1.0"> > > > > <xsl:output method="html" media-type="text/html;charset=iso-8859-1" > > indent="yes" encoding="ISO-8859-1" omit-xml-declaration="yes" /> > > > > <xsl:variable name="date1" select="20080205000000"></xsl:variable> > > <xsl:variable name="date2" select="20080211000000"></xsl:variable> > > <xsl:variable name="option" select="1"></xsl:variable> > > > > <xsl:template match="/"> > > > > <xsl:text disable-output-escaping="yes"><![CDATA[<!DOCTYPE > > html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" > > "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">]]></xsl:text> > > > > <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="es"> > > > > <head> > > <title>Gabinete of Prensa</title> > > <meta http-equiv="Content-Type" content="text/html; > > charset=iso-8859-1" > > /> > > </head> > > > > <body> > > > > <xsl:variable name="filter"> > > <xsl:choose> > > <xsl:when test="$option=1"> > > <xsl:copy-of > > select="//RecursoEx1[F_FIN=$date1 and > > contains(TITULO,'o')]"/></xsl:when> > > <xsl:otherwise> > > <xsl:copy-of > > select="//RecursoEx1[F_FIN=$date2]"/></xsl:otherwise> > > </xsl:choose> > > </xsl:variable> > > > > > > > > > > > > <p>Number: <xsl:value-of > > select="count(exsl:node-set($filter))"/></p> <!-- DON'T FUNCTION --> > > > > <xsl:for-each select="exsl:node-set($filter)"> > > <p><xsl:value-of > > select="exsl:node-set($filter)/TITULO"/></p> <!-- > > DON'T FUNCTION --> > > </xsl:for-each> > > > > </body> > > </html> > > </xsl:template> > > > > </xsl:stylesheet>
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Re: [xsl] Cannot process a result t, Alejandro | Date | Re: [xsl] XSLT Programmer's Referen, Andrew Welch |
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