Re: [xsl] Output sorted XHTML table for a subset of elements

Subject: Re: [xsl] Output sorted XHTML table for a subset of elements
From: "Erik Vullings" <erik.vullings@xxxxxxxxx>
Date: Mon, 26 May 2008 00:16:10 +0200
Another v1.0 example, but without extensions:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
   <xsl:output method="html" encoding="Windows-1252" />
   <xsl:template match="/users">
      <html>
         <body>
            <table>
               <tr>
                  <xsl:for-each select="user">
                     <xsl:sort select="lines" data-type="number"
order="descending"/>
                     <xsl:if test = "lines > 25">
                     	<td><xsl:value-of select="@name"
/>(<xsl:value-of select="lines" />)</td>
                     </xsl:if>
                     <xsl:if test="position() mod 5 = 0">
                     	<xsl:text disable-output-escaping =
"yes">&#x0D;&#x0A;&lt;/tr&gt;&#x0D;&#x0A;</xsl:text>
                     	<xsl:text disable-output-escaping =
"yes">&lt;tr&gt;&#x0D;&#x0A;</xsl:text>
                     </xsl:if>
                  </xsl:for-each>
               </tr>
            </table>
         </body>
      </html>
   </xsl:template>
</xsl:stylesheet>

The </tr><tr> bit is rather ugly, but I find the test="position() mod
5 = 0" rather elegant.

Cheers
Erik

On Sun, May 25, 2008 at 12:53 PM, Martin Honnen <Martin.Honnen@xxxxxx> wrote:
>
> Steven Davies wrote:
>
>> I know my sample data was a bit small but there are a lot more nodes in
>> my actual data set. Here's an attempt at a better example:
>>
>> <users>
>>  <user name="alf"><lines>7</lines></user>
>>  <user name="bert"><lines>78</lines></user>
>>  <user name="charlie"><lines>731</lines></user>
>>  <user name="derek"><lines>62</lines></user>
>>  <user name="edward"><lines>93</lines></user>
>>  <user name="fred"><lines>823</lines></user>
>>  <user name="george"><lines>42</lines></user>
>>  <user name="harry"><lines>28</lines></user>
>>  <user name="ian"><lines>553</lines></user>
>>  <user name="joshua"><lines>92</lines></user>
>>  <user name="kevin"><lines>108</lines></user>
>>  <user name="luke"><lines>192</lines></user>
>> </users>
>>
>> should give the output:
>>
>> <table>
>>  <tr>
>>    <td>fred (823)</td>
>>    <td>charlie (731)</td>
>>    <td>ian (553)</td>
>>    <td>luke (192)</td>
>>    <td>kevin (108)</td>
>>  </tr>
>>  <tr>
>>    <td>edward (93)</td>
>>    <td>joshua (92)</td>
>>    <td>bert (78)</td>
>>    <td>derek (62)</td>
>>    <td>george (42)</td>
>>  </tr>
>>  <tr>
>>    <td>harry (28)</td>
>>  </tr>
>> </table>
>
> Here is an XSLT 1.0 stylesheet making use of exslt:node-set:
>
> <xsl:stylesheet
>  xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>  xmlns:exsl="http://exslt.org/common";
>  exclude-result-prefixes="exsl"
>  version="1.0">
>
>  <xsl:output method="html" indent="yes"/>
>
>  <xsl:param name="cols" select="5"/>
>
>  <xsl:param name="min-lines" select="25"/>
>
>  <xsl:template match="/">
>    <html>
>      <head>
>        <title>Example</title>
>      </head>
>      <body>
>        <xsl:apply-templates select="users"/>
>      </body>
>    </html>
>  </xsl:template>
>
>  <xsl:template match="users">
>    <xsl:variable name="sorted-users-rtf">
>      <data>
>        <xsl:for-each select="user[lines &gt; $min-lines]">
>          <xsl:sort select="lines" data-type="number" order="descending"/>
>          <xsl:copy-of select="."/>
>        </xsl:for-each>
>      </data>
>    </xsl:variable>
>    <xsl:variable name="sorted-users" select="exsl:node-set($sorted-users-rtf)/data/user"/>
>    <table>
>      <tbody>
>        <xsl:apply-templates select="$sorted-users[position() mod $cols = 1]" mode="row"/>
>      </tbody>
>    </table>
>  </xsl:template>
>
>  <xsl:template match="user" mode="row">
>    <tr>
>      <xsl:apply-templates select=". | following-sibling::user[position() &lt; $cols]" mode="cell"/>
>    </tr>
>  </xsl:template>
>
>  <xsl:template match="user" mode="cell">
>    <td>
>      <xsl:value-of select="concat(@name, ' (', lines, ')')"/>
>    </td>
>  </xsl:template>
>
> </xsl:stylesheet>
>
> I think libXSLT supports exsl:node-set.
>
>
> --
>
>        Martin Honnen
>        http://JavaScript.FAQTs.com/

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