RE: [xsl] Changing the Attibute Value

Subject: RE: [xsl] Changing the Attibute Value
From: "Buddhi D. Mahindarathne" <buddhi@xxxxxxxxxxxxxxxxxxx>
Date: Mon, 21 Jul 2008 14:23:04 +0530
This way I tried .. But no luck
	<xsl:template match="VisualObject[@xsi:type='CChamferEx']">
		<xsl:template match="Name[. = 'ChamferedRectangle']">
			<xsl:copy>Fillet</xsl:copy>
		</xsl:template>
	</xsl:template>


-----Original Message-----
From: Abel Braaksma [mailto:abel.online@xxxxxxxxx]
Sent: Monday, July 21, 2008 1:26 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Changing the Attibute Value

Hi Buddhi,

In your code, you match VisualObject and there it stops: you select the
value of the contents (which is always a string), you create a variable
(but don't use it) and there\'s no new apply templates. So the expected
result from your code (without me actually running it) would be the
stringized value of your VisualObject nodes.

Your first question: what Attribute do you mean? There's no node named
"Attribute" and the only actual attribute I see is @xsi:type. Which you
can access by using "@xsi:type" syntax:

<xsl:value-of select="@xsi:type" />

Your second question: this can be done by using the copy template (which

you already have) and removing or changing the template for VisualObject

(see my remark above: it misses an apply-templates to continue the
matching process). After that, you add, for instance:

<xsl:template match="Name[. = 'ChamferedRectangle']">
    <xsl:copy>Fillet</xsl:copy>
</xsl:template>

HTH,
Cheers,
-- Abel --


Buddhi D. Mahindarathne wrote:
> Dear All,
>
> Following is my partial XSLT,
>
> 1. I am not able to access Attribute for changing it
> 2. How do I extract only "ChamferedRectangle" and place "Fillet"
>
>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";>
> 	<xsl:template match="/">
> 		<xsl:apply-templates select="*"/>
> 	</xsl:template>
>     <xsl:template match="@* | node()">
> 	<xsl:copy>
> 	  <xsl:apply-templates select="@* | node()"/>
> 	</xsl:copy>
>     </xsl:template>
>
>    <xsl:template match="VisualObject[@xsi:type='CChamferEx']">

> 		<xsl:copy>
> 			<xsl:variable name="attribute" select = '.'/>
> 			<xsl:value-of select="CFilletEx"/>
> 		</xsl:copy>
> 	</xsl:template>
> </xsl:stylesheet>
>
> Buddhi D. Mahindarathne wrote:
>
>> Dear All,
>> I want to transform following using XSLT 1.0
>>
>> <VisualObject xsi:type="CChamferEx">
>> 	<maxQSwitch>133</maxQSwitch>
>>        <Address>Laser Job.Layer.ChamferedRectangle1</Address>
>>        <Name>ChamferedRectangle1</Name>
>>        <IsMark>true</IsMark>
>>        <Visible>true</Visible>
>> </VisualObject>
>>
>> And get the output like this:
>>
>> <VisualObject xsi:type="CFilletEx">
>> 	<maxQSwitch>133</maxQSwitch>
>>        <Address>Laser Job.Layer.Fillet1</Address>
>>        <Name>Fillet1</Name>
>>        <IsMark>true</IsMark>
>>        <Visible>true</Visible>
>> </VisualObject>
>>
>> Here are the things associated with this,
>>
>> 1. Attribute Change
>> 2. Change last part on DOT separated value (I need to keep the last
>> value with the "Fillet" like [Fillet1] - in the sample number "one")
>> 3. Change the Chamfer to Fillet, but need to keep the last number
like
>> above case.
>>
>> Please help me on this.
>>
>> - Regards
>>   ____            _     _ _     _
>>  | __ ) _   _  __| | __| | |__ (_)
>>  |  _ \| | | |/ _` |/ _` | '_ \| |
>>  | |_) | |_| | (_| | (_| | | | | |
>>  |____/ \__,_|\__,_|\__,_|_| |_|_|

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