Re: [xsl] (simple?) xpath question

Subject: Re: [xsl] (simple?) xpath question
From: mark bordelon <markcbordelon@xxxxxxxxx>
Date: Fri, 29 Aug 2008 13:01:18 -0700 (PDT)
Xmlizer, thanks for the quick response!

Following your post, is there a simple enough xsl solution that could be passed to
XmlDocument.SelectNodes(xslstr) to acheive the nodelist I want?


--- On Fri, 8/29/08, Xmlizer <xmlizer+xsllist@xxxxxxxxx> wrote:

> From: Xmlizer <xmlizer+xsllist@xxxxxxxxx>
> Subject: Re: [xsl] (simple?) xpath question
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Date: Friday, August 29, 2008, 12:12 PM
> that's not possible to do with XPath only
> 
> But with XSLT you can
> 
> Xmlizer
> 
> On Fri, Aug 29, 2008 at 9:06 PM, mark bordelon
> <markcbordelon@xxxxxxxxx> wrote:
> > All *help*!
> >
> > What is the best way to query xml with xpath to get a
> disjoint nodelist? Specifically i want to include just the
> root node alongwith a descendent node.
> >
> > XML:
> >
> > <a>
> > <b>
> > <c>
> > </c>
> > </b>
> > </a>
> >
> > XPATH:
> >
> > //c
> >
> > DESIRED RESULT NODELIST:
> > i.e. not this:
> > <c>
> > </c>
> >
> > but rather this:
> > <a>
> > <c>
> > </c>
> > </a>

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