Subject: Re: [xsl] (simple?) xpath question From: mark bordelon <markcbordelon@xxxxxxxxx> Date: Fri, 29 Aug 2008 13:38:11 -0700 (PDT) |
I'll do this and get back. --- On Fri, 8/29/08, Evan Lenz <evan@xxxxxxxxxxxx> wrote: > From: Evan Lenz <evan@xxxxxxxxxxxx> > Subject: Re: [xsl] (simple?) xpath question > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Date: Friday, August 29, 2008, 1:32 PM > You either need to post more details about the input XML, or > contact > Altova support. Otherwise, it's pure speculation. The > only thing I can > think of is that there's a namespace declaration at the > top that you're > failing to take into account (e.g., > xmlns="http://example.com"). But > even then, the name() function should work if prefixes > aren't being used. > > Evan > > mark bordelon wrote: > > Evan, (and everyone) > > > > Thanks for this great help. > > I am seizing the xpath solution so far (keeping the > xsl solution in the back of my mind as plan B) > > > > However, in Altova Spy neither > > //*[self::a or self::c] > > nor > > //*[name() = 'a' or name() = 'c'] > > > > is returning any results. Syntax is fine, just no > results. > > > > This is the only tool I have for testing, other than > writing code. Is there a configuration in Altova Spy I need > to tweek? > > > > Mark > > > > > > --- On Fri, 8/29/08, Evan Lenz > <evan@xxxxxxxxxxxx> wrote: > > > > > >> From: Evan Lenz <evan@xxxxxxxxxxxx> > >> Subject: Re: [xsl] (simple?) xpath question > >> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > >> Date: Friday, August 29, 2008, 1:14 PM > >> A better approach is to use the self axis along > with true > >> name tests: > >> > >> //*[self::a or self::c] > >> > >> The name() function will work too, but it will > also select > >> <a> and <c> > >> elements regardless of what their namespace is > (and it may > >> give > >> inconsistent results in such cases depending on > whether > >> prefixes are > >> used in the input or not). An actual name test in > the > >> expression, > >> indicating that you're only interested in > <a> and > >> <c> elements that > >> aren't in a namespace, is the way to go. > >> > >> Evan > >> > >> > >> mozer wrote: > >> > >>> Mark, > >>> > >>> //*[name() = 'a' or name() = > 'c'] > >>> > >>> is the right syntax > >>> > >>> Xmlizer > >>> > >>> On Fri, Aug 29, 2008 at 9:57 PM, mark bordelon > >>> > >> <markcbordelon@xxxxxxxxx> wrote: > >> > >>> > >>> > >>>> Thanks, Colin, > >>>> > >>>> > >>>> Although the requirements cannot assume > how many > >>>> > >> levels there are between the root node and the > desired node, > >> your solution points me to something like this. > Does this > >> work? > >> > >>>> //[name() == "a" and name() == > >>>> > >> "c"] > >> > >>>> > >>>> > >>>> --- On Fri, 8/29/08, Colin Paul Adams > >>>> > >> <colin@xxxxxxxxxxxxxxxxxx> wrote: > >> > >>>> > >>>> > >>>>> From: Colin Paul Adams > >>>>> > >> <colin@xxxxxxxxxxxxxxxxxx> > >> > >>>>> Subject: Re: [xsl] (simple?) xpath > question > >>>>> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > >>>>> Date: Friday, August 29, 2008, 12:22 > PM > >>>>> > >>>>> > >>>>>>>>>> "Mark" > == mark > >>>>>>>>>> > > >> bordelon > >> > >>>>>>>>>> > >>>>>>>>>> > > >>>>> <markcbordelon@xxxxxxxxx> > writes: > >>>>> > >>>>> Mark> All *help*! What is > the best > >>>>> > >> way to query > >> > >>>>> xml with xpath > >>>>> Mark> to get a disjoint > nodelist? > >>>>> > >> Specifically i > >> > >>>>> want to include > >>>>> Mark> just the root node > alongwith a > >>>>> > >> descendent > >> > >>>>> node. XML: > >>>>> Mark> <a> <b> > >>>>> > >> <c> > >> > >>>>> </c> </b> </a> > XPATH: > >>>>> > >> //c > >> > >>>>> Mark> DESIRED RESULT NODELIST: > i.e. not > >>>>> > >> this: > >> > >>>>> <c> </c> but > >>>>> Mark> rather this: <a> > >>>>> > >> <c> > >> > >>>>> </c> </a> > >>>>> > >>>>> One possibility is: > >>>>> > >>>>> //*[name() != "b"] > >>>>> > >>>>> It depends on your exact requirements. > >>>>> -- > >>>>> Colin Adams > >>>>> Preston Lancashire
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