Subject: Re: [xsl] (simple?) xpath question From: mark bordelon <markcbordelon@xxxxxxxxx> Date: Fri, 29 Aug 2008 13:09:43 -0700 (PDT) |
mozer: Entering your zpath query into xpath window in XMLspy yields no results. Is this an Altova bug? mark --- On Fri, 8/29/08, mozer <xmlizer@xxxxxxxxx> wrote: > From: mozer <xmlizer@xxxxxxxxx> > Subject: Re: [xsl] (simple?) xpath question > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Date: Friday, August 29, 2008, 1:00 PM > Mark, > > //*[name() = 'a' or name() = 'c'] > > is the right syntax > > Xmlizer > > On Fri, Aug 29, 2008 at 9:57 PM, mark bordelon > <markcbordelon@xxxxxxxxx> wrote: > > Thanks, Colin, > > > > > > Although the requirements cannot assume how many > levels there are between the root node and the desired node, > your solution points me to something like this. Does this > work? > > > > > > //[name() == "a" and name() == > "c"] > > > > > > > > > > --- On Fri, 8/29/08, Colin Paul Adams > <colin@xxxxxxxxxxxxxxxxxx> wrote: > > > >> From: Colin Paul Adams > <colin@xxxxxxxxxxxxxxxxxx> > >> Subject: Re: [xsl] (simple?) xpath question > >> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > >> Date: Friday, August 29, 2008, 12:22 PM > >> >>>>> "Mark" == mark > bordelon > >> <markcbordelon@xxxxxxxxx> writes: > >> > >> Mark> All *help*! What is the best way > to query > >> xml with xpath > >> Mark> to get a disjoint nodelist? > Specifically i > >> want to include > >> Mark> just the root node alongwith a > descendent > >> node. XML: > >> Mark> <a> <b> <c> > >> </c> </b> </a> XPATH: //c > >> Mark> DESIRED RESULT NODELIST: i.e. not > this: > >> <c> </c> but > >> Mark> rather this: <a> <c> > >> </c> </a> > >> > >> One possibility is: > >> > >> //*[name() != "b"] > >> > >> It depends on your exact requirements. > >> -- > >> Colin Adams > >> Preston Lancashire
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