[xsl] XSLT 2.0 replace()

Just learning XSLT 2.0 (and regex), and I'm stumped on the replace() function.

I have XML that looks like this:

<toc> <category title="Structure"> <item title="&lt;attribute&gt;" href="tag.attribute.html" /> <item title="&lt;handler&gt;" href="LzDelegate.html" /> <item title="&lt;event&gt;" href="LzEvent.html" /> . . .

And I want to replace the & with just &, so the HTML that looks like this:

 <body>
     <h1>nav toc</h1>
     <ol>
        <li>Structure</li>
        <ol>
           <li>&lt;lattribute&gt;</li>
           <li>&lt;handler&gt;</li>
           <li>&lt;event&gt;</li>

The closed I've been able to get is this:

  <body>
     <h1>nav toc</h1>
     <ol>
        <li>Structure</li>
        <ol>
           <li>&lt;attribute&amp;gt;</li>
           <li>&lt;handler&amp;gt;</li>
           <li>&lt;event&amp;gt;</li>

So I can change the first &, but not the second. Any ideas? I feel like I must be missing a fundamental concept here.

Here's a fragment of my XSLT:

<ol> <xsl:for-each select="category"> <li> <xsl:value-of select="@title"/> </li> <ol> <xsl:for-each select="item"> <li> <xsl:value-of select="replace(@title, '&lt;', '<')"/> </li> </xsl:for-each> </ol> </xsl:for-each> </ol>

thanks,

Lou

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