Subject: RE: [xsl] xsl:sort with nulls at end From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Mon, 3 Nov 2008 18:19:03 -0000 |
> The issue I have is that if the row is missing that tag, the > sort puts that record first. Ie. Nulls come first. I need the > nulls to come last. > Is there a way to get around this and force the nulls to be last? Add further sort keys: <xsl:for-each select="*"> <xsl:sort select="empty(X)"/> <xsl:sort select="X" order="ascending" data-type="text"/> <xsl:sort select="empty(Y)"/> <xsl:sort select="Y" order="descending" data-type="text"/> <xsl:sort select="empty(Z)"/> <xsl:sort select="Z" order="ascending" data-type="number"/> Note that boolean false() sorts before true(). Michael Kay http://www.saxonica.com/
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