Subject: Re: [xsl] Saxon node matching order From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx> Date: Fri, 28 Nov 2008 14:53:45 +0000 |
2008/11/28 Ed Yau <eyau@xxxxxxxxxxxxxxx>: > Hi all, > > I have a question about how Saxon chooses which node to match next. > > I have some XML that looks a bit like this: > > <x> > <y> > <z>Peter</z> > </y> > <z> </z> > <y> > <z>Jones</> > </y> > </x> > > What I'm trying to achieve is the follow: > > <x> > <z>Peter</z> > <z> </z> > <z>Jones</> > </x> > > With the code below: > > <xsl:template match="x" > > <xsl:apply-templates select="y|z"/> > </xsl:template> > > <xsl:template match="y"> > <xsl:apply-templates select="z"/> > </xsl:template> > > <xsl:template match="z"> > <xsl:copy-of select="."/> > </xsl:template> > > <xsl:template match="@*|*"> > <xsl:copy> > <xsl:apply-templates select="@*|node()"> > </xsl:apply-templates> > </xsl:copy> > </xsl:template> > > > But annoyingly my code seems to be doing this instead: > > <x> > <z>Peter</z> > <z>Jones</z> > <z> </z> > </x> > > It is obviously matching all the <y> tags before the <z> tags. > Does anyone know of a way around this? > Just change: <xsl:template match="x" > <xsl:apply-templates select="y|z"/> </xsl:template> to: <xsl:template match="x" > <xsl:apply-templates/> </xsl:template> In the former you are controlling the order of processing by selecting the nodes to process, in the latter the input controls the order because you process the nodes in document order. -- Andrew Welch http://andrewjwelch.com Kernow: http://kernowforsaxon.sf.net/
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