RE: [xsl] XSLT grouping(?) issue

["Michael Kay" <mike@xxxxxxxxxxxx>]

In XSLT 2.0, use

<xsl:for-each-group group-starting-with="StartOrderGroup">
  <xsl:variable name="start"
select="current-group()[self::StartOrderGroup]"/>
  <xsl:variable name="end" select="current-group()[self::EndOrderGroup]"/>
  <xsl:variable name="group" select="current-group()[. >> $start and . <<
$end]
  <order>
    <xsl:for-each-select="$group">
      <xsl:value-of select="name()"/> - <xsl:value-of select="Id"/>
    </xsl:for-each>
  </order>
</xsl:for-each-group>

plus some formatting as required.

For a 1.0 solution, use sibling recursion, which is a but more difficult.

Michael Kay
http://www.saxonica.com/

> -----Original Message-----
> From: Fredde Hedberg [mailto:syte_orion@xxxxxxxxx]
> Sent: 22 December 2008 10:38
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] XSLT grouping(?) issue
>
> > The problem is solvable with XSLT, provided your input XML is well
> > formed. But your input is not a valid XML document.
> >
> > for e.g., <Id=1/> is not a valid XML fragment, and XML parser
> > complains about it.
>
> My mistake, I apologize. When I simplified my XML I made it
> more bad formed than it really is...
>
> <Orders>
>   <StartOrderGroup>
>     <Id>1</Id>
>   </StartOrderGroup>
>   <Car>
>     <Id>2</Id>
>   </Car>
>   <Car>
>     <Id>3</Id>
>   </Car>
>   <Bus>
>     <Id>4</Id>
>   </Bus>
>   <EndOrderGroup>
>     <Id>5</Id>
>   </EndOrderGroup>
>   <Car>
>     <Id>6</Id>
>   </Car>
>   <Truck>
>     <Id>7</Id>
>   </Truck>
>   <StartOrderGroup>
>     <Id>8</Id>
>   </StartOrderGroup>
>   <Truck>
>     <Id>9</Id>
>   </Truck>
>   <EndOrderGroup>
>     <Id>10</Id>
>   </EndOrderGroup>
> </Orders>
>
> That's at least valid XML :)
> You've given me hope by saying it is solvable. Will this new
> XML-fragment allow you to show me how? That would basically
> save christmas for me...
>
> Regards
>
> Fredde
>
>
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