Subject: Re: [xsl] xsl:for-each-group and identity transform From: Jesper Tverskov <jesper.tverskov@xxxxxxxxx> Date: Fri, 23 Jan 2009 15:07:45 +0100 |
I'm now using: <h> <xsl:copy-of select="./node()"/> </h> instead of: <h> <xsl:copy-of select="descendant::node()"/> </h> But this (my) template works: <xsl:template match="element()|comment()|processing-instruction()" mode="group"> <xsl:copy-of select="current-group()"/> </xsl:template> Your proposal: <xsl:template match="node()" mode="group"> <xsl:copy> <xsl:copy-of select="@* except @the-attributes-you dont-want"/> <xsl:apply-templates mode="group"/> </xsl:copy> </xsl:template> I guess is never going to work, we need "current-group()". I simply can't see how we can get the modified identity template into play. Cheers, Jesper
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