Subject: Re: [xsl] Got xml base path in the xslt file From: Andrew Welch <andrew.j.welch@xxxxxxxxx> Date: Wed, 16 Sep 2009 10:06:21 +0100 |
2009/9/16 Dongsheng Song <dongsheng.song@xxxxxxxxx>: > Hi all, > I use a xsl file to merge multiple xml files, the master xml file like this: > > <doc> > <doc id="Intro" /> > <doc id="Configuration" /> > <doc id="Index" /> > </doc> > > > The xsl file like this: > > <xsl:for-each select="doc/doc"> > <xsl:variable name="fileName"><xsl:value-of select="@id" > /><xsl:text>.xml</xsl:text></xsl:variable> > > <xsl:for-each select="document($fileName)"> > <xsl:copy-of select="doc/div"/> > </xsl:for-each> > </xsl:for-each> > > Because the file path is relative of the xsl file for 'document' > function, I have to put xsl and xml files together. > Can I got the base path of master xml file, so I can store xsl and xml > file separately? In 2.0 you could do something like: /doc/doc/doc(resolve-uri(concat(@id, '.xml'), document-uri(/)))/doc/div or using document() this: /doc/doc/document(concat(@id, '.xml'), /)/doc/div -- Andrew Welch http://andrewjwelch.com Kernow: http://kernowforsaxon.sf.net/
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