Subject: Re: [xsl] Output file name as per input file name with subdirectory From: Ganesh Babu N <nbabuganesh@xxxxxxxxx> Date: Tue, 19 Jan 2010 14:42:44 +0530 |
Dear Selva, Check for xsl:result-document you will get the answer. Regards, Ganesh On Mon, Jan 18, 2010 at 6:58 PM, Selvaganesh <selvaganesh_t@xxxxxxxxxxxxxx> wrote: > Ya Saxon allows the output file, I know the command, how to define the over > XSL. > > -----Original Message----- > From: David Carlisle [mailto:davidc@xxxxxxxxx] > Sent: Monday, January 18, 2010 6:46 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] Output file name as per input file name with subdirectory > > > Please start a new message for a new thread don't just reply to an old > one or it will mess up threaded archives. > > Saxon's command line allows you to specify an output directory, see the > saxon documentation. > > David > > > > Confidentiality Notice: This transmittal is a confidential communication. If you are not the intended recipient, you are hereby notified that you have received this transmittal in error and that any review, dissemination, distribution or copying of this transmittal is strictly prohibited. If you have received this communication in error, please notify this office immediately by reply and immediately delete this message and all of its attachments, if any.
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