Subject: Re: [xsl] How to tell the parser it's not a string but a 'path' to a node? From: "Imsieke, Gerrit, le-tex" <gerrit.imsieke@xxxxxxxxx> Date: Tue, 16 Mar 2010 23:01:32 +0100 |
Good day,
I've just spent 5 hours on this and still can't find a solution.
I have an element called glossary. It contains a link to a different part of the XML file. If I select the path from it, Saxon assumes that I'm now working with a string value, but I'm not. How to I tell it not to treat it as a string but to get the value of the node that the 'string' is pointing to?
----This doesn't work ---- (it outputs the path and not the value of the node where the path is pointing )
</xsl:template> <xsl:template match="glossary"> <xsl:variable name="location" select="'/gset/d/'"/> <xsl:variable name="path" select="."/> <!-- Test data contains gset/goal/description --> <xsl:variable name="fullpath" select="concat($location,$path)"/> .. <xsl:value-of select="$fullpath"/> .. </xsl:template>
----If I "hard code" the value, it works:---- (now I ignore the variables and hardcode a sample path)
</xsl:template> <xsl:template match="glossary"> <xsl:variable name="location" select="'/gset/d/'"/> <xsl:variable name="path" select="."/> <xsl:variable name="fullpath" select="concat($location,$path)"/> .. <xsl:value-of select="/gset/d/gset/goal/description"/> .. </xsl:template>
I'm off to bed to cry myself to sleep!
Kind regards, Jacobus
-- Gerrit Imsieke Geschdftsf|hrer / Managing Director le-tex publishing services GmbH Weissenfelser Str. 84, 04229 Leipzig, Germany Phone +49 341 355356 110, Fax +49 341 355356 510 gerrit.imsieke@xxxxxxxxx, http://www.le-tex.de
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