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Subject: [xsl] How to tell the parser it's not a string but a 'path' to a node? From: Jacobus Reyneke <jacobusreyneke@xxxxxxxxx> Date: Tue, 16 Mar 2010 23:52:43 +0200 |
Good day,
I've just spent 5 hours on this and still can't find a solution.
I have an element called glossary. It contains a link to a different
part of the XML file. If I select the path from it, Saxon assumes that
I'm now working with a string value, but I'm not. How to I tell it not
to treat it as a string but to get the value of the node that the
'string' is pointing to?
----This doesn't work ----
(it outputs the path and not the value of the node where the path is pointing )
</xsl:template> <xsl:template match="glossary">
<xsl:variable name="location" select="'/gset/d/'"/>
<xsl:variable name="path" select="."/> <!-- Test data contains
gset/goal/description -->
<xsl:variable name="fullpath" select="concat($location,$path)"/>
..
<xsl:value-of select="$fullpath"/>
..
</xsl:template>
----If I "hard code" the value, it works:----
(now I ignore the variables and hardcode a sample path)
</xsl:template> <xsl:template match="glossary">
<xsl:variable name="location" select="'/gset/d/'"/>
<xsl:variable name="path" select="."/>
<xsl:variable name="fullpath" select="concat($location,$path)"/>
..
<xsl:value-of select="/gset/d/gset/goal/description"/>
..
</xsl:template>
I'm off to bed to cry myself to sleep!
Kind regards,
Jacobus
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