Subject: [xsl] How to tell the parser it's not a string but a 'path' to a node? From: Jacobus Reyneke <jacobusreyneke@xxxxxxxxx> Date: Tue, 16 Mar 2010 23:52:43 +0200 |
Good day, I've just spent 5 hours on this and still can't find a solution. I have an element called glossary. It contains a link to a different part of the XML file. If I select the path from it, Saxon assumes that I'm now working with a string value, but I'm not. How to I tell it not to treat it as a string but to get the value of the node that the 'string' is pointing to? ----This doesn't work ---- (it outputs the path and not the value of the node where the path is pointing ) </xsl:template> <xsl:template match="glossary"> <xsl:variable name="location" select="'/gset/d/'"/> <xsl:variable name="path" select="."/> <!-- Test data contains gset/goal/description --> <xsl:variable name="fullpath" select="concat($location,$path)"/> .. <xsl:value-of select="$fullpath"/> .. </xsl:template> ----If I "hard code" the value, it works:---- (now I ignore the variables and hardcode a sample path) </xsl:template> <xsl:template match="glossary"> <xsl:variable name="location" select="'/gset/d/'"/> <xsl:variable name="path" select="."/> <xsl:variable name="fullpath" select="concat($location,$path)"/> .. <xsl:value-of select="/gset/d/gset/goal/description"/> .. </xsl:template> I'm off to bed to cry myself to sleep! Kind regards, Jacobus
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