Re: [xsl] Selecting all elements which have an attribute that matches a given pattern

[Martin Honnen <Martin.Honnen@xxxxxx>]

Etheridge, Stephen wrote:

> I have an XML file (a schema in fact) that is many thousands of lines
> long and I need to edit it (i.e transform it).  There are numerous
> elements of type <xs:element> all of which have a "name" attribute.
> Some of those name attributes end with the string "List", e.g.
> "MilkTypeList".  For those elements, I want to apply a template to add
> an additional <xs:element>.  I am having great trouble crafting the
> correct "match" for my <xsl:template>.  I have tried contains() and
> matches() but my editor (Oxygen) states that those cannot be used as a
> pattern and my reading supports that.  Can anyone help?

You can certainly use e.g.
  <xsl:template match="xs:element[contains(@name, 'List')]">
or
  <xsl:template match="xs:element[matches(@name, 'list', 'i')]">

--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/