Re: [xsl] URI's, double backslashes and regular expressions

[David Carlisle <davidc@xxxxxxxxx>]

On 28/10/2010 19:51, Neil Owens wrote:
> I just can't figure out the syntax here
>
> I'm passing a directory location into Saxon as a parameter.  Only I need to make every '\' character in the (windows) directory path a '\\' for the uri in the transform.  As it's only the transform that needs this I thought I'd do the conversion in the transform.  And it's beaten me.

why? UROs never use \ to separate components they always use / and \ 
isn't an escape character in xpath strings so you never need to double \/

> The command line param is: ...path="C:\Documents and Settings\Adminis
> trator\My Documents\Projects\Transform\OutputFiles"
>
> I've got this neatly passed into the transform with:
>
> <xsl:param name="path"></xsl:param>
> ...
> <xsl:template match="Log">
>          <xsl:value-of select= replace($path, '\\', '\\')" />

>          <xsl:variable name="Command" select="concat($path, '\\OutputFiles\\Command-output.xml')" />
>          <xsl:result-document method="xml" href="{$Command}">
>          .....
>
>
> But fails and I just can't figure out how to achieve setting the result-document

href to equal "C:\\Documents and Settings\\Administrator\\My 
Documents\\Projects\\Transform\OutputFiles"

you want a URI not a windows file path with doubled \

file:///c:/Documents%20and%20Settings\\Administrator\\My%20Documents\\Projects\\Transform\OutputFiles

David