Subject: [xsl] Accessing the XML file name from an XSL Transform From: Neil Owens <neil_owens@xxxxxxxxxxx> Date: Wed, 10 Nov 2010 14:25:00 +0000 |
I need to access the filename (well, actually without the extension, but that's a simple RegEx) in an XSL Transform Obviously, I can pass a xsl:param name= to a XSLT transform that contains the filename, but I can't see how to achieve this when using Saxon's -s: command line option where -s: contains a directory and not a file. I'm sure there's got to be a way to find out the XML doc name that's being transformed, but I just can't find it. Is this possible?
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Unique id based on the po, Gábor Tóth | Thread | Re: [xsl] Accessing the XML file na, Michael Kay |
Re: [xsl] Saxon documentation pages, Michael Müller-Hille | Date | Re: [xsl] Accessing the XML file na, Michael Kay |
Month |