RE: [xsl] selecting nodes based on sibling values

["Fabien Tillier" <f.tillier@xxxxxxxx>]

Well
The level = 50 are linked to the level = 40 above (they are always after,
first 40, then 50)
And the 50 ones have the start of keycode identical to the level = 40
keycode.

Regards,
Fabien

-----Message d'origine-----
De : Michael Kay [mailto:mike@xxxxxxxxxxxx]
Envoyi : mardi 23 novembre 2010 16:49
@ : xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Objet : Re: [xsl] selecting nodes based on sibling values

I wasn't quite sure what you meant by the condition on keycode, e.g.
whether they all need to be consecutive and whether they all need to
appear before the next level 40.

Michael Kay
Saxonica

On 23/11/2010 15:33, Fabien Tillier wrote:
> Hum. This one doesn't work.
> I get 5 as an answer... I assume the keycode should be used somewhere within
the for-each-group
>
> -----Message d'origine-----
> De : Michael Kay [mailto:mike@xxxxxxxxxxxx]
> Envoyi : mardi 23 novembre 2010 16:25
> @ : xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Objet : Re: [xsl] selecting nodes based on sibling values
>
>
> <xsl:variable name="gpsizes">
> <xsl:for-each-group select="row" group-starting-with="row[level='40']">
> <xsl:sequence select="count(current-group()) - 1"/>
> </xsl:for-each-group>
> </xsl:variable>
> <xsl:value-of select="max($gpsizes)"/>
>
> Michael Kay
> Saxonica
>
> On 23/11/2010 14:45, Fabien Tillier wrote:
>> Hi List.
>> Let's say I have an XML like below...
>>
>> <data>
>> 	<row>
>> 		<level>40</level>
>> 		<keycode>1254.45.12</keycode>
>> 	</row>
>> 	<row>
>> 		<level>50</level>
>> 		<keycode>1254.45.12.7</keycode>
>> 	</row>
>> 	<row>
>> 		<level>50</level>
>> 		<keycode>1254.45.12.8</keycode>
>> 	</row>
>> 	<row>
>> 		<level>50</level>
>> 		<keycode>1254.45.12.9</keycode>
>> 	</row>
>>
>> 	<row>
>> 		<level>40</level>
>> 		<keycode>99.25.6</keycode>
>> 	</row>
>> 	<row>
>> 		<level>50</level>
>> 		<keycode>99.25.6.45</keycode>
>> 	</row>
>> 	<row>
>> 		<level>50</level>
>> 		<keycode>99.25.6.46</keycode>
>> 	</row>
>> </data>
>>
>> What could be the XPath expression to get the maximum number of nodes of
>> level=50 in data those keycode starts like the level=40 line ?
>> Here the answer would be 3 as the maximum number of level = 50 nodes for
>> a given level = 40 is 3
>> I have tried several things, but I am stuck....
>> (I am using XSLT 2.0 on Saxon)
>>
>>
>> Thanks for lending me some neurons...
>> Best regards,
>> Fabien