Re: [xsl] compare two nodes (the child elements, not the string values) in XSLT 1.0

[Wolfhart Totschnig <wolfhart@xxxxxxxxxxxxx>]

> How about this (not very cool):
>
> test="concat(path/person/first, '|', path/person/first, '|', path/person/first) 
>     = concat(first, '|', middle, '|', last)

This does not work. The concat() function transforms the node sets into 
strings, and so the expression "concat(path/person/first, '|', 
path/person/middle, '|', path/person/last)" takes the values of the 
<first>, <middle>, and <last> elements of the *first* <person> element 
(the string value of a node set is by definition the string value of the 
first node in the node set) and concatenates them. So the test you 
propose will always yield "false" unless the context node happens to be 
equal to the first <person> element.

Wolfhart