Subject: Re: [xsl] Children with the same name From: Andrew Welch <andrew.j.welch@xxxxxxxxx> Date: Mon, 21 Nov 2011 16:43:40 +0000 |
On 21 November 2011 16:34, Merrilees, David <David.Merrilees@xxxxxxxxxxxx> wrote: > Hi > > I'm stuck with an Xpath. How can I select child nodes with the same name? The names are arbitrary. So far I have this, which does not work: > Input > > <array> > <item/> > <nope/> > <item>4</item> > <item>5</item> > <wibble/> > <item>six</item> > <wibble>stuff</wibble> > <item>item</item> > <no/> > </array> > > Desired output > > <array> > <item>4</item> > <item>5</item> > <wibble/> > <item>six</item> > <wibble>stuff</wibble> > <item>item</item> > </array> Hi, Define a key: <xsl:key name="elements-by-name" match="*" use="name()"/> Tweak that match pattern if needed, then you can do: <xsl:apply-templates select="array/*[exists(key('elements-by-name', name())[2])]"/> cheers andrew -- Andrew Welch http://andrewjwelch.com
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