Subject: RE: [xsl] layout problem From: Roelof Wobben <rwobben@xxxxxxxxxxx> Date: Thu, 8 Dec 2011 11:22:31 +0000 |
Oke, What Im trying to do is to make this layout (http://www.notepadchaos.com) in xml and xslt. What I have so far is this : home.xsl : <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:import href="../utilities/master.xsl"/> <xsl:import href="../utilities/sections.xsl"/> <xsl:template match="data"> <xsl:call-template name="section-content"/> </xsl:template> </xsl:stylesheet> master.xsl : <?xml version="1.0" encoding="utf-8" ?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:import href="../utilities/common.xsl"/> <xsl:import href="../utilities/sections.xsl"/> <xsl:output method="xml" doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN" doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd" omit-xml-declaration="yes" encoding="UTF-8" indent="yes" /> <xsl:template match="/"> <html> <body> <xsl:call-template name="head"/> <xsl:apply-templates /> <xsl:call-template name="bottom"/> </body> </html> </xsl:template> </xsl:stylesheet> sections.xsl : <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template name="section-content"> <div id="outer"> <div id="container"> <div id="search"> <form method="get" id="searchform" action="http:/test.tamarawobben.nl/"> <input type="text" value="" name="s" id="s" class="txtField" /> <input type="submit" id="searchsubmit" class="btnSearch" value="Find It ;" /> </form> </div> <div id="title"> <h2>Tamara Wobben </h2> </div> <div id="content"> <div class="col01"> <xsl:for-each select="section/entry"> <div class="post"> <h2><xsl:value-of select="title"/></h2> <div class="post-inner"> <h4><xsl:value-of select="heading"/></h4> <xsl:copy-of select="description/*"/> <xsl:copy-of select="body/*"/> </div> </div> </xsl:for-each> </div> </div> </div> </div> </xsl:template> </xsl:stylesheet> common.xsl : <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template name="head"> <head> <title><xsl:value-of select="$website-name"/> - <xsl:value-of select="$page-title"/></title> <link rel="stylesheet" type="text/css" href="{$workspace}/assets/css/style.css"/> <link rel="alternate" type="application/rss+xml" title="Notepad Chaos RSS Feed" href="http://www.notepadchaos.com/feed/" /> <link rel="pingback" href="http://www.notepadchaos.com/xmlrpc.php" /> <link rel="alternate" type="application/rss+xml" title="Notepad Chaos Feed" href="http://www.notepadchaos.com/feed/" /> <link rel="alternate" type="application/rss+xml" title="Notepad Chaos Comments Feed" href="http://www.notepadchaos.com/comments/feed/" /> <link rel="EditURI" type="application/rsd+xml" title="RSD" href="http://www.notepadchaos.com/xmlrpc.php?rsd" /> <link rel="wlwmanifest" type="application/wlwmanifest+xml" href="http://www.notepadchaos.com/wp-includes/wlwmanifest.xml" /> <link rel='index' title='Notepad Chaos' href='http://www.notepadchaos.com/' /> </head> </xsl:template> <xsl:template name="bottom"> <div id="footer-holder"> <div class="footer"> <a href="http://www.notepadchaos.com/">Notepad Chaos</a><br /> <a href="http://www.notepadchaos.com/">Notepad Chaos</a> uses the <a href="http://www.notepadchaos.com">"Notepad Chaos v2"</a> theme. </div> <span class="evaneckard"> <a href="http://www.evaneckard.com">Evan Eckard Design</a> </span> <span class="smashing"> <a href="http://www.smashingmagazine.com">Smashing Magazine</a> </span> <span class="rss"> <a href="http://www.notepadchaos.com/feed/">RSS</a> </span> </div> </xsl:template> </xsl:stylesheet> I use this layout ( https://github.com/bauhouse/sym-bauhouse/tree/master/pages) as a example. But if there a better way I will take that. Roelof ---------------------------------------- > Date: Thu, 8 Dec 2011 10:52:21 +0000 > From: andrew.j.welch@xxxxxxxxx > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] layout problem > > On 8 December 2011 10:34, Roelof Wobben <rwobben@xxxxxxxxxxx> wrote: > > > Hello, > > > I have this xml : > > > Why don't I get to see the output as I expected on the screen ? > > Someone might put in the effort for you, but you really need to > re-post a 'small complete runnable example', containing only what's > necessary to demonstrate your problem. You don't have a root matching > template, and only one named template, so it needs an initial template > setting - as you didnt mention it its hard to know if thats > intentional. > > Also, remember the helpful guide when you are new to xslt - avoid > named templates and avoid for-each, use the apply-templates and many > small templates. > > -- > Andrew Welch > http://andrewjwelch.com
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