Subject: Re: [xsl] read array From: Michel Hendriksen <michel.hendriksen@xxxxx> Date: Wed, 21 Dec 2011 12:43:45 +0100 |
Only two or could there be more or less? On Wed, Dec 21, 2011 at 12:42 PM, henry human <henry_human@xxxxxxxx> wrote: > Hi > The XML > > <?xml version="1.0"?> > <root> > <Invoice> > <DocumentReference> > <ID>100</ID> > </DocumentReference> > </Invoice> > <Invoice> > <DocumentReference> > <ID>200</ID> > </DocumentReference> > </Invoice> > </root> > > Output should be: 1.100_2.200 > > best regards > > > ----- Urspr|ngliche Message ----- > Von: Andrew Welch <andrew.j.welch@xxxxxxxxx> > An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Cc: > Gesendet: 11:38 Mittwoch, 21.Dezember 2011 > Betreff: Re: [xsl] read array > > On 21 December 2011 10:33, henry human <henry_human@xxxxxxxx> wrote: >> Ther are two elements "ID" in the xml >> I will read them and concat together: >> <xsl:for-each select="root/Invoice/DocumentReference/ID"> >> ........... >> </xsl:for-each> >> Concat([1].ID + [2].ID > > There are many ways... you need to re-post with an example and the > required output. > > > > -- > Andrew Welch > http://andrewjwelch.com
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