Subject: [xsl] [XPath 3.0] How to do partial function application on the min() function? From: "Costello, Roger L." <costello@xxxxxxxxx> Date: Mon, 29 Oct 2012 21:50:20 +0000 |
Hi Folks, I would like to fix one argument of the min() function to 2 and leave the other argument undefined, thus producing a partially applied function. Then, I would like to give the partially applied function a value. Here's what I tried: let $min2 := min((?,2)) return $min2(3) I get this error: Unexpected token "?" in path expression What's the correct way to accomplish this? /Roger
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