Subject: Re: [xsl] Only child test From: Andre Cusson <ac@xxxxxxxxxxxxx> Date: Thu, 10 Oct 2013 10:34:44 -0400 |
Wouldn't "last() eq 1" or "last() gt 1" be both the fastest and clearest? ac
../*[2]
This is the first expression I thought about -- then saw that PQQP5QP;P0P2 P!P5P4P>P2 has already offered it.
Cheers, Dimitre
On Wed, Oct 9, 2013 at 9:38 PM, Karl Stubsjoen <kstubs@xxxxxxxxx> wrote:Just curious how other's might approach a test to determine if the current node is *not* an only child. This works fine but it feels a little heavy to me. Thoughts?
<xsl:if test="(count(preceding-sibling::*) + count(following-sibling::*)) > 1"> <hr/> </xsl:if>
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