Re: [xsl] Escaping Characters in replace()

[David Carlisle <davidc@xxxxxxxxx>]

On 15/10/2013 17:44, Nathan Tallman wrote:
> Thank you, David. Unfortunately, I still get ". after processing...

Presumably the template never matched.

> (I'm transforming XML to HML, btw.)
>
> Also, a question. Why didn't you need to escape the period in the
> third argument of replace()?

You need \. to mean a literal . in a regular expression, not in the 
replacement text.

> (When I inert one, my processor throws an
> error; so, I understand it's wrong, but not why. Also, I seem to be
> able to delete the backslash in front of the period in the second
> argument without causing problems... Why is that?)

". is a legal regex but matches a " followed by any character

replace(.,'"."','."')

would change "x to ."


David

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