Re: [xsl] Pattern notation for preceding-sibling

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Heiko Niemann kontakt@xxxxxxxxxxxxxxxx wrote:

> Elements A,B,B,N,E,B,C are contained in element foo.

> Now I want A,N to be returned, so my first guess is, that this might work:
>
> /foo/E/preceding-sibling::(A,N)
>
> But it does not, so I either have to write
>
> /foo/E/(preceding-sibling::A, preceding-sibling::N) or

> So, is there a (short) notation that I missed so far, that does what I
> expected /foo/E/preceding-sibling::(A,N) to do?

No, I don't think so.