Subject: Re: [xsl] Collect data from a whole map hierarchy, then use it in a topic From: "rick@xxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 15 Jun 2023 19:26:30 -0000 |
Thank you Martin. I first want to get a list of all uribs throughout the whole hierarchy, then I can integrate the rest of your code. I have a recursive function to process the uribs but I am not sure how to get a cumulative list. Thank you for your generous help. <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:math="http://www.w3.org/2005/xpath-functions/math" xmlns:rq="http://www.frameexpert.com/functions" exclude-result-prefixes="xs math rq" version="3.0" expand-text="yes"> <xsl:output indent="yes"/> <xsl:variable name="map-uri-collection" select="//*/@href[matches(.,'(dita(map)?|xml)$','i')]/resolve-uri(. ,base-uri(.))[doc-available(.)]"/> <xsl:variable name="topic-uri-collection" select="rq:get-uri-collection(.,$map-uri-collection)"/> <xsl:template match="/"> <!-- Further processing here. --> </xsl:template> <xsl:function name="rq:get-uri-collection"> <xsl:param name="doc"/> <xsl:param name="uri-collection"/> <xsl:variable name="doc-uri-collection" select="$doc//@href[matches(.,'(dita(map)?|xml)$','i')]/resolve-u ri(. ,base-uri(.))[doc-available(.)]"/> <!--<xsl:variable name="uri" select="resolve-uri($uri, base-uri($doc))"/>--> <xsl:if test="count($doc-uri-collection) > 0"> <xsl:for-each select="$doc-uri-collection"> <xsl:message select="."></xsl:message> <xsl:variable name="doc" select="doc(.)"/> <xsl:sequence select="rq:get-uri-collection($doc,$uri-collection)"/> </xsl:for-each> </xsl:if> </xsl:function> </xsl:stylesheet> From: Martin Honnen martin.honnen@xxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Sent: Thursday, June 15, 2023 11:44 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] Collect data from a whole map hierarchy, then use it in a topic On 6/15/2023 4:46 PM, rick@xxxxxxxxxxxxxx <mailto:rick@xxxxxxxxxxxxxx> wrote: I am still trying to find the best way to navigate through an entire ditamap structure, collect certain data, then reprocess the map to insert the pertinent data into one of the topics. Earlier this week I posted code using an accumulator, but when I reprocess the map using a different mode, it only shows the each topicbs collected data. Here is an attempt to avoid the various modes and the accumulator by trying to simply select the various URIs and then their documents and finally the elements you seemed to want to collect with XPath: <xsl:stylesheet xmlns:xsl= <http://www.w3.org/1999/XSL/Transform> "http://www.w3.org/1999/XSL/Transform" xmlns:xs= <http://www.w3.org/2001/XMLSchema> "http://www.w3.org/2001/XMLSchema" xmlns:math= <http://www.w3.org/2005/xpath-functions/math> "http://www.w3.org/2005/xpath-functions/math" xmlns:map= <http://www.w3.org/2005/xpath-functions/map> "http://www.w3.org/2005/xpath-functions/map" exclude-result-prefixes="xs math map" version="3.0" expand-text="yes"> <xsl:variable name="topic-uri-collection1" select= <mailto://*/@href%5bmatches(.,'(dita(map)?|xml)$','i')%5d/resolve-uri(.,base- uri(.))%5bdoc-available(.)%5d> "//*/@href[matches(.,'(dita(map)?|xml)$','i')]/resolve-uri(. ,base-uri(.))[doc-available(.)]"/> <xsl:variable name="topic-docs" select="$topic-uri-collection1 ! doc(.)"/> <xsl:variable name="summary-data" select="$topic-docs ! (.//tool | .//spare | .//supply)"/> <xsl:output indent="yes"/> <xsl:template match="/"> <map-data> <summary> <xsl:for-each-group select="$summary-data" group-by="normalize-space(.)"> <xsl:sort select="local-name(.)"/> <xsl:sort select="normalize-space(.)"/> <xsl:element name="{local-name(.)}"><xsl:attribute name="quantity" select="sum(current-group()/@quantity) <mailto:/@quantity)%22/%3e%7bnormalize-space(.)%7d%3c/xsl:element> "/>{normalize-space(.)}</xsl:element> </xsl:for-each-group> </summary> </map-data> </xsl:template> </xsl:stylesheet> Perhaps that makes it easier for you to then use the global variable and process the data with a mode. Note that the above with a simple XPath selection will only work if you have that topic map referencing all other documents, but not if referenced documents can as well reference further documents; in the latter case you would need a recursive function. XSL-List info and archive <http://www.mulberrytech.com/xsl/xsl-list> EasyUnsubscribe <http://lists.mulberrytech.com/unsub/xsl-list/612310> (by email <> )
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