Aw: Re: [xsl] XSLT2 Change country name to alpha-2

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

The second argument to the key function is an XPath expression, remove
the single quote delimiters you have in your code.

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gesendet.Am 03.07.23, 02:45 schrieb "LEGAULT, PHILLIP
plegault@xxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>:

  Tried it like this:

  <codes>

  <country alpha-2="US" name = "United States"/>

  </codes>

  <xsl:key name="alpha-by-name" match="codes/country" use="@name"/>

  <xsl:output method="xml" version="1.0" encoding="UTF-8"
  indent="yes"/>

  <primarysourcecountry><xsl:value-of select="key('alpha-by-name',
  '/records/sf:ConsumerCountry_GCC__c',
  $codes)/@alpha-2"/></primarysourcecountry>

  Does not work.

  -----Original Message-----

  From: Martin Honnen martin.honnen@xxxxxx
  <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>

  Sent: Sunday, July 2, 2023 7:20 AM

  To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx

  Subject: [EXTERNAL]Re: [xsl] XSLT2 Change country name to alpha-2

  On 02.07.2023 13:09, LEGAULT, PHILLIP plegault@xxxxxxxxxx wrote:

  > I get the country in like United States.

  >

  >

  >

  > I have this,

  Then declare a key

  <xsl:key name="alpha-by-name" match="codes/country" use="@name"/>

  load e.g. <xsl:param name="codes" select="doc('codes.xml')"/> and
  where you need the code from the country name use e.g.

  key('alpha-by-name', country, $codes)/@alpha-2

  I wonder how often that will fail for e.g.

  >

  > <codes>

  >

  >

  >

  > <country alpha-2="BS" name = "Bahamas (the)"/>

  >

  >

  or

  >

  > <country alpha-2="IO" name = "British Indian Ocean Territory
  (the)"/>

  >

  >

  or

  >

  > <country alpha-2="KY" name = "Cayman Islands (the)"/>

  >

  >

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